Oc-windows.ru

IT Новости из мира ПК
2 просмотров
Рейтинг статьи
1 звезда2 звезды3 звезды4 звезды5 звезд
Загрузка...

Java lang arrayindexoutofboundsexception 8

java.lang.ArrayIndexOutOfBoundsException: length=8; index=8 #101

Comments

Copy link Quote reply

m-o commented Aug 18, 2015

Hi, I am having strange problem. I am recording vidoe files from Android surface(originally from GoPro3) and I am adding audio track.
I get exception on some files. I can play those files, ffprobe does not show anything strange. And the error shows only in combination with audio track.

Example:
Load mp4 — load video8, extract video track, add to new Movie, save — ok;
Load mp4 — load video9, extract video track, add to new Movie, save — ok;
Load mp4 — load video8. extract video, add to new Movie, load .aac file, add to movie, ok;
Load mp4 — load video9. extract video, add to new Movie, load .aac file, add to movie, error;

Here is my code:

And here is full exception:

The problem is, I do not know where to look for the error. Is it in video or audio track?
Also, when I tried to use FragmentedMp4Builder — the movie was saved. But library I use for reading the final file had problems reading it, so FragmentedMp4Builder is not a solution for me.
The error log shows error on line:

Thanks for repsonse!

This comment has been minimized.

Copy link Quote reply

m-o commented Aug 18, 2015

Edit: I tried to use diferent audio file, and the problems are the same: vide8 ok, video9 error.

This comment has been minimized.

Copy link Quote reply

sannies commented Aug 18, 2015

Are you using one of the latest builds?
When I do:

in the master branch both videos just work fine (Do I assume correctly that the audio is silence?)

That should help!

This comment has been minimized.

Copy link Quote reply

m-o commented Aug 18, 2015

I had version 1.0.6. When I added 1.1.2 I am getting error on both files:

And yes, the file is mute. It is just for testing purposses, I will be adding real audio later.

This comment has been minimized.

Copy link Quote reply

sannies commented Aug 18, 2015

Ohhh my .
I accidentally used List.sort(Comparator) which is only available in Java 8 and therefore not on Android and earlier version of the JSDK. I’m replacing it with Collections.sort(List, Comparator) and build a new build. Gimme 10 minutes

This comment has been minimized.

Copy link Quote reply

sannies commented Aug 18, 2015

This comment has been minimized.

Copy link Quote reply

m-o commented Aug 18, 2015

Hi, thank you for the prompt fix. But after I updated the library and cleaned the project, when I try to combine files I get similar error:

This comment has been minimized.

Copy link Quote reply

sannies commented Aug 18, 2015

Oh my, there was a second one. Could you please grab the master branch and
build it on your own. I removed this second List.sort that caused you to
trip but there might be more. I don’t have the time to build a new release
right now or do a thorough review.

Marek Ovečka notifications@github.com schrieb am Di., 18. Aug. 2015 um
20:49 Uhr:

Hi, I updated the library and cleaned the project, but when I try to
combine files I get similar error:

Process: com.example.marek.audiorecorder, PID: 19590
java.lang.NoSuchMethodError: No interface method sort(Ljava/util/Comparator;)V in class Ljava/util/List; or its super classes (declaration of ‘java.util.List’ appears in /system/framework/core-libart.jar)
at com.googlecode.mp4parser.authoring.builder.DefaultMp4Builder$InterleaveChunkMdat.(DefaultMp4Builder.java:650)
at com.googlecode.mp4parser.authoring.builder.DefaultMp4Builder$InterleaveChunkMdat.(DefaultMp4Builder.java:646)
at com.googlecode.mp4parser.authoring.builder.DefaultMp4Builder.build(DefaultMp4Builder.java:127)


Reply to this email directly or view it on GitHub
#101 (comment).

Читать еще:  База данных javascript

This comment has been minimized.

Copy link Quote reply

m-o commented Aug 19, 2015

Ok, thank you. I will try to build it.

This comment has been minimized.

Copy link Quote reply

m-o commented Aug 19, 2015

Hi, I made build but it gives me error on all files:

E/AndroidRuntime﹕ FATAL EXCEPTION: Timer-0
Process: easycoremedia.vucaster, PID: 18007
java.lang.ArrayIndexOutOfBoundsException: length=0; index=0
at com.googlecode.mp4parser.authoring.samples.DefaultMp4SampleList.(DefaultMp4SampleList.java:57)
at com.coremedia.iso.boxes.mdat.SampleList.(SampleList.java:33)
at com.googlecode.mp4parser.authoring.Mp4TrackImpl.(Mp4TrackImpl.java:61)
at com.googlecode.mp4parser.authoring.container.mp4.MovieCreator.build(MovieCreator.java:57)
at com.googlecode.mp4parser.authoring.container.mp4.MovieCreator.build(MovieCreator.java:38)
at easycoremedia.vucaster.BufferingMuxer.createFinalMix(BufferingMuxer.java:145)
at easycoremedia.vucaster.BufferingMuxer.access$400(BufferingMuxer.java:33)
at easycoremedia.vucaster.BufferingMuxer$StopRecording.run(BufferingMuxer.java:84)
at java.util.Timer$TimerImpl.run(Timer.java:284)

I do not know, if I made some mistake when building the .jar.
I will be off the internet for few days, so I will be back to this issue after weekend.

This comment has been minimized.

Copy link Quote reply

m-o commented Aug 25, 2015

Hi, I am still getting this error. I dot know, what I am doing wrong. Could you please create build off current version? Thank you!

This comment has been minimized.

Copy link Quote reply

sannies commented Aug 26, 2015

Please find 1.1.4 here:

2015-08-25 15:09 GMT+02:00 Marek Ovečka notifications@github.com:

Hi, I am still getting this error. I dot know, what I am doing wrong.
Could you please create build off current version? Thank you!


Reply to this email directly or view it on GitHub
#101 (comment).

Понимание Array IndexOutofbounds Исключение в Java

Java поддерживает создание и манипулирование массивами , как структуру данных. Индекс массива — это целочисленное значение, значение которого находится в интервале [0, n-1], где n — размер массива. Если сделан запрос на отрицательный или индекс, который больше или равен размеру массива, то JAVA выдает исключение ArrayIndexOutOfBounds. Это не похоже на C / C ++, где не выполняется проверка индекса привязки.

ArrayIndexOutOfBoundsException — исключение времени выполнения, выдаваемое только во время выполнения. Компилятор Java не проверяет эту ошибку во время компиляции программы.

// Индекс общей причины выходит за пределы

public class NewClass2

public static void main(String[] args)

for ( int i= 0 ; i

Ошибка выполнения выдает исключение:

Выход:

Здесь, если вы внимательно посмотрите, массив имеет размер 5. Следовательно, при доступе к его элементу с помощью цикла for максимальное значение индекса может быть 4, но в нашей программе оно увеличивается до 5 и, следовательно, является исключением.

Давайте посмотрим еще один пример использования arraylist:

// Еще один пример с индексом вне границ

public class NewClass2

public static void main(String[] args)

ArrayList lis = new ArrayList<>();

Ошибка выполнения здесь немного более информативна, чем предыдущая

Давайте поймем это немного подробнее

  • Индекс здесь определяет индекс, к которому мы пытаемся получить доступ.
  • Размер дает нам информацию о размере списка.
  • Поскольку размер равен 2, последний индекс, к которому мы можем получить доступ (2-1) = 1, и, следовательно, исключение

Правильный способ доступа к массиву:

Обработка исключения:

  • Использовать цикл for-each : он автоматически обрабатывает индексы при доступе к элементам массива. Пример-
  • Используйте Try-Catch: рассмотрите возможность включения вашего кода в оператор try-catch и соответственно обработайте исключение. Как уже упоминалось, Java не позволит вам получить доступ к недопустимому индексу и обязательно выдаст исключение ArrayIndexOutOfBoundsException. Однако мы должны быть осторожны внутри блока оператора catch, потому что, если мы не обработаем исключение надлежащим образом, мы можем скрыть его и, таким образом, создать ошибку в вашем приложении.

Эта статья предоставлена Rishabh Mahrsee . Если вам нравится GeeksforGeeks и вы хотите внести свой вклад, вы также можете написать статью и отправить ее по почте на contrib@geeksforgeeks.org. Смотрите свою статью, появляющуюся на главной странице GeeksforGeeks, и помогите другим вундеркиндам.

Пожалуйста, напишите комментарии, если вы обнаружите что-то неправильное, или вы хотите поделиться дополнительной информацией по обсуждаемой теме

Читать еще:  Код ошибки 0xc000007b

Solving java.lang.ArrayindexOutOfBoundsException: 1 in Java

The error ArrayIndexOutOfBoundsException : 1 means index 1 is inval >ArrayIndexOutfBoundsException comes when your code, mostly for loop tries to access an inval >IndexOutOfBoundsException which is used to throw error related to invalid index e.g. try to access outside of length in String etc.

An array is a data structure which is the base for many advanced data structure e.g. list, hash table or a binary tree. The array stores elements in the contiguous memory location and it can also have multiple dimension e.g. a two-dimensional array. You can use the 2D array to represent matrix, a board in games like Tetris, Chess and other board games.

A good knowledge of data structure and the algorithm is a must for any good programmer. You should read a good introductory book e.g. Introduction to Algorithms by Thomas Cormen to learn more about array in Java.

Understanding ArrayIndexOutOfBoundsException

This error comes when you are accessing or iterating over array directly or indirectly. Directly means you are dealing with array type e.g. String[] or main method, or an integer[] you have created in your program. Indirectly means via Collection classes which internally use an array e.g. ArrayList or HashMap.

Now let’s understand what information the associated error message gives us:
java.lang.ArrayIndexOutOfBoundsException: 0 means you are trying to access index 0 which is invalid, which in turn means the array is empty.

Here is a Java program which reproduces this error by accessing the first element of the empty array i.e. array with zero length:

You can see the accessing first element of an empty array resulted in the ArrayIndexOutOfBoundsException in Java.

java.lang.ArrayindexOutOfBoundsException: 1 means index 1 is invalid, which in turn means array contains just one element. Here is a Java program which will throw this error:

Similarly, java.lang.ArrayIndexOutOfBoundsException: 2 means index 2 is invalid, which means array has just 2 elements and you are trying to access the third element of the array.

Sometimes when a programmer makes switch from C/C++ to Java they forget that Java does the bound checking at runtime, which is a major difference between C++ and Java Array. You should read Core Java Volume 1 By Cay S. Horstmann if you are learning Java and knows C++. The author often highlights the key difference between C++ and Java while teaching important concepts.

Here is nice slide of some good tips to avoid ArrayIndexOutOfBondsException in Java:

How to avoid ArrayIndexOutOfBoundsException in Java

In order to avoid the java.lang.ArrayIndexOutOfBoundsException, you should always do the bound check before accessing array element e.g.

Always remember that array index starts at 0 and not 1 and an empty array has no element in it. So accessing the first element will give you the java.lang.ArrayIndexOutOfBoundsException : 0 error in Java.

You should always pay to one-off errors while looping over an array in Java. The programmer often makes mistakes which result in either missing first or last element of the array by messing 1st element or finishing just before the last element by incorrectly using the , >= or operator in for loops. For example, following program will never print the last element of the array. The worst part is there won’t be any compile time error or runtime exception. It’s pure logical error which will cause incorrect calculation.

You can see the first element of array i.e. 2 is never get printed. There is no compile time or runtime error, though.

Here are few handy tips to avoid ArrayIndexOutOfBoundsException in Java:

  1. Always remember that array is zero based index, first element is at 0th index and last element is at length — 1 index.
  2. Pay special attention to start and end condition of loop.
  3. Beware of one-off errors like above.
Читать еще:  Foreach java arraylist

Common reasons of java.lang.ArrayIndexOutOfBoundsException in Java

The ArrayIndexOutOfBoundsException, also known as java.lang.ArrayIndexOutOfBoundsExcepiton is one of the most common errors in Java program. It occurs when Java program tries to access an inval >String[] name = <"abc">then trying to access name[1] will give java.lang.ArrayIndexOutOfBoundsException: length=1; index=1 error because index 1 is invalid here. Why? because index in Java array starts with zero rather than 1, hence in an array of just one element the only valid index is index zero. This was one of the most common scenarios which cause several million of ArrayIndexOutOfBoundsException daily. Sometimes it just a plain programming error but sometimes if an array is populated outside and if there is an error on feed than also you get java.lang.ArrayIndexOutOfBoundsException in Java.

In this article, I will share with you some of the common reasons of ArrayIndexOutOfBoundsExcpetion and their solution. This will give you enough experience to deal with this error in future.

In order to solve ArrayIndexOutOfBoundsException, just remember following key details about array in Java:

1) The array index in Java starts at zero and goes to length — 1 , for example in an integer array int[] primes = new int[10] , the first index would be zero and last index out be 9 (10 -1)

2) Array index cannot be negative, hence prime[-1] will throw java.lang.ArrayIndexOutOfBoundsException .

3) The maximum array index can be Integer.MAX_VALUE -1 because the data type of index is int in Java and the maximum value of int primitive is Integer .MAX_VALUE. See Big Java: Early Objects, 5th edition by Cay S. Horstmann to learn more about array data structure in Java.

Now, let’s see some of the common examples of ArrayIndexOutOfBoundsException in Java

java.lang.ArrayIndexOutOfBoundsException length=0 index=0

This is the classic case of accessing an empty array. Since length is zero it means the array is empty and the index is zero means we are trying to access the first element of the array. This happens when you try to access an array without checking its length, as shown below.

When you run this program you will get following error:

A solution to this problem is to always access array after checking array length, as shown in the good code snippet.

java.lang.ArrayIndexOutOfBoundsException: length=1; index=1

This the second most popular reason of ArrayIndexOutOfBoundsException in Java. Here you are trying to access an array by its length. If you remember, the maximum val >index = length then you get this error. This usually happens when you use or >= sign in for loop while looping over an array in Java.

If you run this code, you will get following error :

This is because 10 is not a valid index for an array of length 10. The valid index is only from 0 to 9. See a good data structure book e.g. Introduction to Algorithm to learn more about array data structure in general.

This is the third common reasons of millions of ArrayIndexOutOfBoundsException. In this case, you are trying to access the array using a negative index. There could be different reasons why index becomes negative but the bottom line is you should not access an array with the negative index.

Ссылка на основную публикацию
Adblock
detector